JEE Main & Advanced Mathematics Indefinite Integrals Question Bank Integration by Substitution

  • question_answer
     \[\int_{{}}^{{}}{\frac{{{\sec }^{2}}x\ dx}{\sqrt{{{\tan }^{2}}x+4}}=}\]

    A)            \[\log \left[ \tan x+\sqrt{{{\tan }^{2}}x+4} \right]+c\]               

    B)            \[\frac{1}{2}\log \left[ \tan x+\sqrt{{{\tan }^{2}}x+4} \right]+c\]

    C)            \[\log \left[ \frac{1}{2}\tan x+\frac{1}{2}\sqrt{{{\tan }^{2}}x+4} \right]+c\]

    D)            None of these

    Correct Answer: A

    Solution :

                       Put \[t=\tan x\Rightarrow dt={{\sec }^{2}}x\,dx,\] then            \[\int_{{}}^{{}}{\frac{{{\sec }^{2}}x\,dx}{\sqrt{{{\tan }^{2}}x+4}}}=\int_{{}}^{{}}{\frac{1}{\sqrt{{{t}^{2}}+{{2}^{2}}}}}\,dt\]                                \[=\log [\tan x+\sqrt{{{\tan }^{2}}x+4}]+c.\]


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