A) \[x=a\cos t\]
B) \[x=2a\cos t\]
C) \[x=2at\]
D) \[x=2a{{\sin }^{2}}t\]
Correct Answer: D
Solution :
To evaluate \[\int_{{}}^{{}}{\frac{dx}{x\sqrt{2ax-{{x}^{2}}}}},\] the suitable substitution is \[(2a{{\sin }^{2}}t=x).\]
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