A) \[\log \cos (\log x)+c\]
B) \[\log \sin (\log x)+c\]
C) \[\log \sec (\log x)+c\]
D) \[\log \text{cosec}(\log x)+c\]
Correct Answer: C
Solution :
Put \[\log x=t\Rightarrow \frac{1}{x}dx=dt\], therefore \[\int_{{}}^{{}}{\frac{\tan (\log x)}{x}dx=\int_{{}}^{{}}{\tan t\ dt}}\] \[=\log \sec t+c=\log \ \sec (\log x)+c\].You need to login to perform this action.
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