A) \[2\cos \sqrt{x}+c\]
B) \[2\sin \sqrt{x}+c\]
C) \[\sin \sqrt{x}+c\]
D) \[\frac{1}{2}\cos \sqrt{x}+c\]
Correct Answer: B
Solution :
Put \[\sqrt{x}=t\Rightarrow \frac{1}{2\sqrt{x}}dx=dt\].
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