JEE Main & Advanced Mathematics Indefinite Integrals Question Bank Integration by Parts

  • question_answer
    \[\int{{{e}^{x}}(1+\tan x+{{\tan }^{2}}x)\,\,dx=}\]            [Karnataka CET 1999]

    A)                 \[{{e}^{x}}\sin x+c\]

    B)                 \[{{e}^{x}}\cos x+c\]

    C)                 \[{{e}^{x}}\tan x+c\]

    D)   \[{{e}^{x}}\sec x+c\]

    Correct Answer: C

    Solution :

                    \[I=\int{{{e}^{x}}(1+\tan x+{{\tan }^{2}}x})dx\]                 Þ\[\int{{{e}^{x}}(1+\tan x+{{\tan }^{2}}x)dx=\int{{{e}^{x}}(\tan x+{{\sec }^{2}}x)}\,dx.}\]                \[I={{e}^{x}}\tan x+c\]          \[(\because \,\int{{{e}^{x}}[f(x)+{f}'(x)]+x={{e}^{x}}f(x)+c}).\]


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