A) \[(x+1){{e}^{x}}+c\]
B) \[(x-1){{e}^{x}}+c\]
C) \[x{{e}^{x}}+1+c\]
D) \[x{{e}^{x}}-1+c\]
Correct Answer: B
Solution :
\[\int_{{}}^{{}}{x{{e}^{x}}dx}=x.{{e}^{x}}-\int_{{}}^{{}}{1.{{e}^{x}}dx}\] \[=x{{e}^{x}}-{{e}^{x}}+c={{e}^{x}}(x-1)+c\].
You need to login to perform this action.
You will be redirected in
3 sec
