A) \[\frac{\sin kx}{k}+c\]
B) \[\frac{\cos kx}{k}+c\]
C) \[\frac{\sin x}{k}+c\]
D) \[-\frac{x\,\cos kx}{k}+\frac{\sin kx}{{{k}^{2}}}+c\]
Correct Answer: D
Solution :
\[I=\int_{{}}^{{}}{x\sin kx\,dx}=\frac{-x\cos kx}{k}+\frac{\sin kx}{{{k}^{2}}}+c\]
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