A) \[x+x\log x+c\]
B) \[x\log x-x+c\]
C) \[{{x}^{2}}\log x+c\]
D) \[\frac{1}{x}\log x+x+c\]
Correct Answer: B
Solution :
\[\int_{{}}^{{}}{\log x\,dx}=x\log x-\int_{{}}^{{}}{x\,.\,\frac{1}{x}\,dx+c=x\log x-x+c}\] Note : Students should remember this question as a formula.
You need to login to perform this action.
You will be redirected in
3 sec
