• # question_answer If $i=\sqrt{-1}$, then $1+{{i}^{2}}+{{i}^{3}}-{{i}^{6}}+{{i}^{8}}$ is equal to [RPET 1995] A) $2-i$ B) 1 C) 3 D) $-1$

Solution :

$1+{{i}^{2}}+{{i}^{3}}-{{i}^{6}}+{{i}^{8}}=1-1-i+1+1=2-i$.

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