JEE Main & Advanced Mathematics Applications of Derivatives Question Bank Increasing and Decreasing Function

  • question_answer
    If \[f(x)={{x}^{3}}-10{{x}^{2}}+200x-10\], then [Kurukshetra  CEE 1998]

    A)            \[f(x)\]is decreasing in \[]-\infty ,10]\] and increasing in \[[10,\,\infty [\]

    B)            \[f(x)\]is increasing in \[]-\infty ,10]\] and decreasing in \[[10,\,\infty [\]

    C)            \[f(x)\]is increasing throughout real line

    D)            \[f(x)\]is decreasing throughout real line

    Correct Answer: C

    Solution :

               \[f(x)={{x}^{3}}-10{{x}^{2}}+200x-10\]                    \[f'(x)=3{{x}^{2}}-20x+200\]                    For increasing \[f'(x)>0\] Þ \[3{{x}^{2}}-20x+200>0\]                    \[3\text{ }\left[ {{x}^{2}}-\frac{20}{3}x+\frac{200}{3}+\frac{100}{9}-\frac{100}{9} \right]>0\]                    \[\Rightarrow 3\text{ }\left[ {{\left( x-\frac{10}{3} \right)}^{2}}+\frac{500}{9} \right]>0\] \[\Rightarrow 3\text{ }{{\left( x-\frac{10}{3} \right)}^{2}}+\frac{500}{3}>0\]                    Always increasing throughout real line.


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