• # question_answer The maximum number of molecules is present in [CBSE PMT 2004] A)                 0.5 g of ${{H}_{2}}$ gas               B)                 10 g of ${{O}_{2}}$ gas C)                 15 L of ${{H}_{2}}$ gas at STP    D)                 5 L of ${{N}_{2}}$ gas at STP

In $22.4l$ of ${{H}_{2}}$ maximum number of molecules $=6.023\times {{10}^{23}}$                    In $1l$ of ${{H}_{2}}$ maximum number of molecules $=\frac{6.023\times {{10}^{23}}}{22.4}$                                 In $15l$of ${{H}_{2}}$ maximum number of molecules $=\frac{6.023\times {{10}^{23}}}{22.4}\times 15$ $=4.03\times {{10}^{23}}$ molecules.