A) 22.4 litre
B) 2.24 litre
C) 0.224 litre
D) 11.2 litre
Correct Answer: C
Solution :
\[\underset{(40+12+16\times 3)\ =100gm}{\mathop{CaC{{o}_{3}}}}\,\hat{\to }CaO+\underset{22.4litre}{\mathop{C{{O}_{2}}}}\,\uparrow \] \[\because \] At S.T.P. \[100g\]\[CaC{{O}_{3}}\] produce=\[22.4litre\]of \[C{{O}_{2}}\] \[\therefore \] At S.T.P. \[1g\] \[CaC{{O}_{3}}\] produce = \[\frac{22.4}{100}=.224litre\] of \[C{{O}_{2}}\]
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