JEE Main & Advanced Chemistry States of Matter Question Bank Ideal gas equation and Related gas laws

  • question_answer
    Equal amounts of two gases of molecular weight 4 and 40 are mixed. The pressure of the mixture is 1.1 atm. The partial pressure of the light gas in this mixture is [CBSE PMT 1991]

    A)                 0.55 atm             

    B)                 0.11 atm

    C)                 1 atm   

    D)                 0.12 atm

    Correct Answer: C

    Solution :

               No. of moles of lighter gas \[=\frac{m}{4}\]                    No. of moles of heavier gas \[=\frac{m}{40}\]                    Total no. of moles \[=\frac{m}{4}+\frac{m}{40}=\frac{11m}{40}\]                    Mole fraction of lighter gas \[=\frac{\frac{m}{4}}{\frac{11m}{40}}=\frac{10}{11}\]                    Partial pressure due to lighter gas \[={{P}_{o}}\times \frac{10}{11}\]                                 \[=1.1\times \frac{10}{11}=1atm.\]

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