A) 1/2 atm
B) 1/273 atm
C) 2 atm
D) 273 atm
Correct Answer: A
Solution :
\[{{T}_{1}}={{273}^{o}}C=273+{{273}^{o}}K={{546}^{o}}K\] \[{{T}_{2}}={{0}^{o}}C=273+{{0}^{o}}C={{273}^{o}}K\] \[{{P}_{1}}=1\] ; \[{{P}_{2}}=?\] According to Gay-Lussac?s law \[\frac{{{P}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}}{{{T}_{2}}}\] \[\therefore \] \[{{P}_{2}}=\frac{{{P}_{1}}{{T}_{2}}}{{{T}_{1}}}=\frac{1\times {{273}^{o}}K}{{{546}^{o}}K}\] atm; \[\frac{1}{2}\] atm.
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