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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Hydrogenion concentration pH scale and buffer solution

  • question_answer
    The \[pH\] of a solution obtained by mixing \[50\,\,ml\] of \[0.4\,\,N\,\,HCl\] and \[50\,\,ml\] of \[0.2\,\,N\,\,NaOH\]is                 [KCET 1996]

    A)                 \[-\log 2\]           

    B)                 \[-\log 0.2\]

    C)                 1.0         

    D)                 2.0

    Correct Answer: C

    Solution :

               N.eq. for \[HCl=\frac{0.4}{1000}\times 50=0.02\]                    N.eq. for \[NaOH=\frac{0.2}{1000}\times 50=0.1\]                    Now \[[O{{H}^{-}}]\] left \[=0.1-0.02\]                    \[[O{{H}^{-}}]=.08=8\times {{10}^{-2}}\]M                                 \[pOH=-\log 8\times {{10}^{-2}}\]M ; \[pOH=1.0\]


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