A) \[s{{p}^{2}},\,\,s{{p}^{3}},\,\,{{d}^{2}}s{{p}^{3}}\]
B) \[s{{p}^{3}},\,\,s{{p}^{3}}{{d}^{2}},\,\,s{{p}^{3}}{{d}^{2}}\]
C) \[sp,\,\,s{{p}^{3}}d,\,\,s{{p}^{3}}{{d}^{2}}\]
D) \[sp,\,\,s{{p}^{2}},\,\,s{{p}^{3}}\]
Correct Answer: C
Solution :
Atom/Ion Hybridisation \[NO_{2}^{+}\] sp \[S{{F}_{4}}\] \[s{{p}^{3}}d\] with one lone pair of electron \[PF_{6}^{-}\] \[s{{p}^{3}}{{d}^{2}}\]
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