A) sp - hybridisation
B) \[s{{p}^{2}}\]- hybridisation
C) \[s{{p}^{3}}\]- hybridisation
D) \[s{{p}^{3}}{{d}^{2}}\] - hybridization
Correct Answer: C
Solution :
In Diborane boron shows \[s{{p}^{3}}\]?hybridization.
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