A) \[S{{F}_{6}}\]
B) \[B{{F}_{4}}^{-}\]
C) \[PC{{l}_{5}}\]
D) \[BO_{3}^{3-}\]
Correct Answer: A
Solution :
S-atom in \[S{{F}_{6}}\] has \[s{{p}^{3}}{{d}^{2}}\] hybridisation. So, the structure of \[S{{F}_{6}}\] will be octahedral.
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