A) Decreases
B) Increases
C) Doubles
D) Remains unchanged
Correct Answer: A
Solution :
As p-character increases the bond angle decreases. In \[sp\] - p-character \[\frac{1}{2}\], bond angle - \[{{180}^{o}}\] In \[s{{p}^{2}}\]- p-character \[\frac{2}{3}\], bond angle - \[{{120}^{o}}\] In \[s{{p}^{3}}\]- p-character \[\frac{3}{4}\], bond angle - \[{{109}^{o}}\]
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