A) \[s{{p}^{3}}\]
B) \[s{{p}^{2}}\]
C) \[sp\]
D) None of these
Correct Answer: C
Solution :
s-character in \[sp=\frac{1}{2}\times 100=50%\] s-character in \[s{{p}^{2}}=\frac{1}{3}\times 100=33.3%\] s-character in \[s{{p}^{3}}=\frac{1}{4}\times 100=25%\] Hence, maximum s-character is found in sp-hybridisation.
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