A) \[{{d}_{{{x}^{2}}}},{{d}_{xz}}\]
B) \[{{d}_{xy}},{{d}_{yz}}\]
C) \[{{d}_{{{x}^{2}}-{{y}^{2}}}},{{d}_{{{z}^{2}}}}\]
D) \[{{d}_{xz}},{{d}_{{{x}^{2}}-{{y}^{2}}}}\]
Correct Answer: C
Solution :
In the formation of \[{{d}^{2}}s{{p}^{3}}\]hybrid orbitals two \[(n-1)d\]orbitals of e.g., set [i.e., \[(n-1)\,d{{z}^{2}}\] and \[(n-1)d{{x}^{2}}-{{y}^{2}}\]orbitals] one ns and three np [\[n{{p}_{x}},n{{p}_{y}}\] and \[n{{p}_{z}}\]] orbitals combine together and form six \[{{d}^{2}}s{{p}^{3}}\] hybrid orbitals.
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