A) Increases
B) Decreases
C) Becomes zero
D) Does not change
Correct Answer: A
Solution :
s-character increases with increase in bond angle. Hybridization s% Angle Sp 50 \[{{180}^{o}}\] \[s{{p}^{2}}\] 33.3 \[{{120}^{o}}\] \[s{{p}^{3}}\] 25 \[{{109.28}^{o}}\] \[s{{p}^{3}}{{d}^{1}}\] 20 \[{{90}^{o}}\] and \[{{120}^{o}}\]
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