JEE Main & Advanced
Chemistry
Coordination Chemistry
Question Bank
Hybridisation and Geometry
question_answer
Considering \[{{H}_{2}}O\] as a weak field ligand, the number of unpaired electrons in \[{{[Mn{{({{H}_{2}}O)}_{6}}]}^{2+}}\] will be (At. No. of Mn = 25) asas a ajkk [CBSE PMT 2004]
A)Two
B)Four
C)Three
D)Five
Correct Answer:
D
Solution :
\[M{{n}^{25}}\xrightarrow{{}}3{{d}^{5}}+4{{s}^{2}}\] \[M{{n}^{2+}}\xrightarrow{{}}3{{d}^{5}}\] In presence of weak ligand field, there will be no pairing of electrons. So it will form a high spin complex. i.e. the number of unpaired electrons = 5.