A) \[x=c({{x}^{2}}+{{y}^{2}})\]
B) \[x=c({{x}^{2}}-{{y}^{2}})\]
C) \[x+c({{x}^{2}}-{{y}^{2}})=0\]
D) None of these
Correct Answer: B
Solution :
It can be written in the form of homogeneous equation \[\frac{dy}{dx}=\frac{{{x}^{2}}+{{y}^{2}}}{2xy}\] Now solve it by putting \[y=vx\] and \[\frac{dy}{dx}=v+x\frac{dv}{dx}\].
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