A) \[150\,c{{m}^{2}}\]
B) \[120\,c{{m}^{2}}\]
C) \[50\,c{{m}^{2}}\]
D) \[100\,c{{m}^{2}}\]
Correct Answer: C
Solution :
Area of \[\Delta PQR\] \[=\sqrt{s(s-a)(s-b)(s-c)}\] where \[s=\frac{50+50+80}{2}=90\] Area\[=\sqrt{90(90-50)(90-50)(90-80)}\] \[=1200\,c{{m}^{2}}\] Area of \[\Delta PQR=\Delta \,\text{Area}\,\text{of}\,\Delta PSR\] \[=1200\,c{{m}^{2}}\] \[\therefore \]Area of Rhombus= Area of \[\Delta PQR+\text{Area}\,\text{of}\,\Delta PSR\] \[=(1200+1200)c{{m}^{2}}=2400\,c{{m}^{2}}\] The area of grass field for 48 cows to graze\[=2400\,c{{m}^{2}}\] \[\therefore \]Area of the grass field for each cow to graze \[=\frac{2400}{48}=50\,c{{m}^{2}}\]
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