A) \[\left( 8+\sqrt{2} \right)cm\]
B) \[\left( 8+4\sqrt{2} \right)cm\]
C) \[\left( 4+8\sqrt{2} \right)cm\]
D) \[100\sqrt{3}\,{{m}^{2}}\]
Correct Answer: B
Solution :
Sides of an isosceles right triangle are a, a and \[\sqrt{2}a.\] Area of isosceles right triangle \[=\frac{1}{2}{{a}^{2}}\Rightarrow 8c{{m}^{2}}=\frac{1}{2}{{a}^{2}}\Rightarrow a=4\,cm\] Perimeter of the triangle \[=(a+a+\sqrt{2}a)cm\] \[=(8+4\sqrt{2})cm\]
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