A) \[2104.56\text{ }c{{m}^{2}},\text{ }2104.56\text{ }c{{m}^{2}}\]
B) \[4209.22\text{ }c{{m}^{2}},\,2104.56\text{ }c{{m}^{2}}\]
C) \[1204.61\text{ }c{{m}^{2}},\text{ }1204.61\text{ }c{{m}^{2}}\]
D) \[2014.61\text{ }c{{m}^{2}},1204.61\text{ }c{{m}^{2}}\]
Correct Answer: A
Solution :
We have, a = 40 cm, b = 40 cm and c = 18 cm \[s=\frac{40+40+18}{2}=49\,cm\] \[\therefore \] Area of one triangular piece \[=\sqrt{49\times 9\times 9\times 31}=350.76\,c{{m}^{2}}\] \[\therefore \] Area of 6 triangular piece \[350.76\times 6\] \[=21.04.56\,c{{m}^{2}}\] Similarly, area of another 6 triangular piece \[=21.04.56\,c{{m}^{2}}\]
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