A) Decreases
B) Increases
C) Remains the same
D) Any of the above depending upon the relative values of \[{{R}_{1}}\] and \[{{R}_{2}}\]
Correct Answer: A
Solution :
Equivalent resistance in the second case \[={{R}_{1}}+{{R}_{2}}=R\] Now, we know that \[P\propto \frac{1}{R}\] Since in the second case the resistance \[({{R}_{1}}+{{R}_{2}})\]is higher than that in the first case (R1). Therefore power dissipation in the second case will be decreased.
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