JEE Main & Advanced Physics Thermodynamical Processes Question Bank Heat Engine Refrigerator and Second Law of Thermodynamics

  • question_answer
    An ideal heat engine exhausting heat at \[{{77}^{o}}C\] is to have a 30% efficiency. It must take heat at                 [BCECE 2004]

    A)            \[{{127}^{o}}C\]                  

    B)            \[{{227}^{o}}C\]

    C)            \[{{327}^{o}}C\]                  

    D)             \[{{673}^{o}}C\]

    Correct Answer: B

    Solution :

                       \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}\] Þ \[\frac{30}{100}=1-\frac{350}{{{T}_{1}}}\]            Þ \[\frac{350}{{{T}_{1}}}=1-\frac{50}{100}=\frac{70}{100}=\frac{7}{10}\]Þ \[{{T}_{1}}=500\,K=227{}^\circ C\]


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