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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Heat Engine Refrigerator and Second Law of Thermodynamics

  • question_answer
    An engine is supposed to operate between two reservoirs at temperature 727°C and 227°C. The maximum possible efficiency of such an engine is          [UPSEAT 2005]

    A)            1/2                                           

    B)             1/4

    C)            3/4

    D)             1

    Correct Answer: A

    Solution :

               \[\eta =\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}=\frac{(273+727)-(273+227)}{273+727}\]\[=\frac{1000-500}{1000}=\frac{1}{2}\]


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