JEE Main & Advanced Physics Thermodynamical Processes Question Bank Heat Engine Refrigerator and Second Law of Thermodynamics

  • question_answer
    An ideal heat engine working between temperature T1­ and T2 has an efficiency h, the new efficiency if both the source and sink temperature are doubled, will be        [DPMT 2000]

    A)            \[\frac{\eta }{2}\]              

    B)             \[\eta \]

    C)            \[2\eta \]                               

    D)            \[3\eta \]

    Correct Answer: B

    Solution :

                       In first case \[{{\eta }_{1}}=\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}\]            In second case \[{{\eta }_{2}}=\frac{2{{T}_{1}}-2{{T}_{2}}}{2{{T}_{1}}}\]\[=\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}=\eta \]


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