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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Heat Engine Refrigerator and Second Law of Thermodynamics

  • question_answer
    A Carnot?s engine is made to work between 200°C and 0°C first and then between 0°C and ?200°C. The ratio of efficiencies of the engine in the two cases is      [KCET 2002]

    A)            1.73 : 1                                    

    B)            1 : 1.73

    C)            1 : 1                                          

    D)            1 : 2

    Correct Answer: B

    Solution :

                       In first case \[{{\eta }_{1}}=1-\frac{{{T}_{2}}}{{{T}_{1}}}=1-\frac{(273+0)}{(273+200)}=\frac{200}{473}\]                    In second case \[{{\eta }_{2}}=1-\frac{(273-200)}{(273+0)}=\frac{200}{273}\]            Þ  \[\frac{{{\eta }_{1}}}{{{\eta }_{2}}}=\frac{1}{\left( \frac{473}{273} \right)}=1:1.73\]


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