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JEE Main & Advanced Physics Thermodynamical Processes Question Bank Heat Engine Refrigerator and Second Law of Thermodynamics

  • question_answer
    The coefficient of performance of a Carnot refrigerator working between \[{{30}^{o}}C\]and \[{{0}^{o}}C\] is                    [UPSEAT 2002]

    A)            10  

    B)            1

    C)            9    

    D)            0

    Correct Answer: C

    Solution :

                       Coefficient of performance            \[K=\frac{{{T}_{2}}}{{{T}_{1}}-{{T}_{2}}}=\frac{273}{303-273}=\frac{273}{30}=9\]


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