2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Thermodynamical Processes

JEE Main & Advanced Physics Thermodynamical Processes Question Bank Heat Engine Refrigerator and Second Law of Thermodynamics

  • question_answer
    A Carnot engine operates between \[{{227}^{o}}C\] and \[{{27}^{o}}C.\] Efficiency of the engine will be               [DCE 1999; BHU 2004]

    A)            \[\frac{1}{3}\]                      

    B)            \[\frac{2}{5}\]

    C)            \[\frac{3}{4}\]                      

    D)            \[\frac{3}{5}\]

    Correct Answer: B

    Solution :

               \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}=1-\frac{300}{500}=\frac{2}{5}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner