JEE Main & Advanced Physics Thermodynamical Processes Question Bank Heat Engine Refrigerator and Second Law of Thermodynamics

  • question_answer
    The efficiency of Carnot's engine operating between reservoirs, maintained at temperatures \[{{27}^{o}}C\] and \[-{{123}^{o}}C,\] is                                    [DPMT 2002, 03; BVP 2004]

    A)            50%                                          

    B)            24%

    C)            0.75%                                      

    D)            0.4%

    Correct Answer: A

    Solution :

               \[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}=1-\frac{(273+123)}{(273+27)}=1-\frac{150}{300}=\frac{1}{2}=50%\]


You need to login to perform this action.
You will be redirected in 3 sec spinner