A) Q / 4
B) Q / 3
C) Q / 2
D) 2Q / 3
Correct Answer: B
Solution :
\[\because \ \eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}=\frac{W}{{{Q}_{1}}}\]\[{{T}_{2}}=300\,K\] where \[{{Q}_{1}}=\] heat absorbed, \[{{Q}_{2}}=\] heat rejected Þ \[1-\frac{T/3}{T}=\frac{W}{{{Q}_{1}}}\] Þ \[\frac{2}{3}=\frac{W}{{{Q}_{1}}}=\frac{{{Q}_{1}}-{{Q}_{2}}}{{{Q}_{1}}}\] Þ \[\frac{2}{3}=1-\frac{{{Q}_{2}}}{{{Q}_{1}}}\] Þ \[\frac{{{Q}_{2}}}{{{Q}_{1}}}=\frac{1}{3}\] Þ \[{{Q}_{2}}=\frac{{{Q}_{1}}}{3}=\frac{Q}{3}\]You need to login to perform this action.
You will be redirected in
3 sec