A) \[{{T}_{2}}=273\,\,K\]
B) \[{{T}_{2}}=0\,\,K\]
C) \[{{T}_{1}}=273\,\,K\]
D) \[{{T}_{1}}=0\,\,K\]
Correct Answer: B
Solution :
\[\eta =1-\frac{{{T}_{2}}}{{{T}_{1}}}\] for 100% efficiency h = 1 which gives T2 = 0 K.
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