A) 1800 J/cycle
B) 1000 J/cycle
C) 2000 J/cycle
D) 1600 J/cycle
Correct Answer: D
Solution :
\[\eta =\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}-\frac{W}{Q}\]Þ \[Q=\left( \frac{{{T}_{1}}}{{{T}_{1}}-{{T}_{2}}} \right)\,W\] \[=\frac{600}{(600-300)}\times 800\]=1600 J
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