• question_answer Iodine is formed when potassium iodide reacts with a solution of [MNR 1984; MP PET/PMT 1998] A) $ZnS{{O}_{4}}$ B) $CuS{{O}_{4}}$ C) ${{(N{{H}_{4}})}_{2}}S{{O}_{4}}$ D) $N{{a}_{2}}S{{O}_{4}}$

$CuS{{O}_{4}}+2KI\,\to \,Cu{{I}_{2}}+{{K}_{2}}S{{O}_{4}}$ $2Cu{{I}_{2}}\,\to \,\underset{\text{Cuprous iodide}\,\,\,\,\,\,\,\,\,\,}{\mathop{2CuI\,\,\,\,\,\,\,+\,\,\,\,\,{{I}_{2}}}}\,$