• question_answer When chlorine reacts with cold and dilute solution of sodium hydroxide, the products obtained are [CBSE PMT 1998] A) $C{{l}^{-}}+Cl{{O}^{-}}$ B) $C{{l}^{-}}+ClO_{2}^{-}$ C) $C{{l}^{-}}+ClO_{3}^{-}$ D) $C{{l}^{-}}+ClO_{4}^{-}$

$2NaOH+C{{l}_{2}}\to \underset{\underset{N{{a}^{+}}+C{{l}^{-}}}{\mathop{\downarrow }}\,}{\mathop{NaCl}}\,+\underset{\underset{N{{a}^{+}}+OC{{l}^{-}}}{\mathop{\downarrow }}\,}{\mathop{NaOCl}}\,+{{H}_{2}}O$