• # question_answer Iodine and hypo react to produce [DPMT 2001] A) $N{{a}_{2}}S$ B) $HCl$ C) $N{{a}_{2}}{{S}_{4}}{{O}_{6}}$ D) $N{{a}_{2}}S{{O}_{3}}$

Solution :

$2N{{a}_{2}}{{S}_{2}}{{O}_{3}}+{{I}_{2}}\to N{{a}_{2}}{{S}_{4}}{{O}_{6}}+2NaI$.

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