A) \[\frac{1}{9}m\]
B) \[\frac{1}{10}m\]
C) \[\frac{1}{11}m\]
D) \[\frac{10}{11}m\]
Correct Answer: C
Solution :
\[\frac{G\times 100}{{{x}^{2}}}=\frac{G\times 10000}{{{(1-x)}^{2}}}\]\[\Rightarrow \,\,\frac{10}{x}=\frac{100}{1-x}\,\Rightarrow \,x=\frac{1}{11}m\]
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