A) \[{{(Kg)}^{1/2}}\]
B) \[{{(Kg)}^{-1/2}}\]
C) \[{{(Kg)}^{2}}\]
D) \[{{(Kg)}^{-2}}\]
Correct Answer: A
Solution :
\[v=\sqrt{2gR}\]\\[\frac{{{v}_{1}}}{{{v}_{2}}}=\sqrt{\frac{{{g}_{1}}}{{{g}_{2}}}\times \frac{{{R}_{1}}}{{{R}_{2}}}}=\sqrt{g\times K}\]= \[{{(Kg)}^{1/2}}\]
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