JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Gravitation Potential

  • question_answer
    The escape velocity for the earth is \[{{v}_{e}}\]. The escape velocity for a planet whose radius is four times and density is nine times that of the earth, is                                  [MP PET 2003]

    A)             \[36\,{{v}_{e}}\]       

    B)             \[12\,{{v}_{e}}\]

    C)             \[6\,{{v}_{e}}\]         

    D)             \[20\,{{v}_{e}}\]

    Correct Answer: B

    Solution :

                    \[v\propto R\sqrt{\rho }\]\ \[\frac{{{v}_{p}}}{{{v}_{e}}}=\frac{{{R}_{p}}}{{{R}_{e}}}\times \sqrt{\frac{{{\rho }_{p}}}{{{\rho }_{e}}}}=4\times \sqrt{9}=12\] Þ \[{{v}_{p}}=12{{v}_{e}}\]


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