JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Gravitation Potential

  • question_answer
    The change in potential energy, when a body of mass m is raised to a height nR from the earth's surface is (R = Radius of earth)                            [MP PMT 1996]

    A)             \[mgR\frac{n}{n-1}\]

    B)               nmgR

    C)             \[mgR\frac{{{n}^{2}}}{{{n}^{2}}+1}\]

    D)               \[mgR\frac{n}{n+1}\]

    Correct Answer: D

    Solution :

                    \[\Delta U=\frac{mgh}{1+\frac{h}{R}}=\frac{mg\,nR}{1+\frac{nR}{R}}=\frac{nm\,gR}{n+1}\]


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