JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Gravitation Potential

  • question_answer
    The least velocity required to throw a body away from the surface of a planet so that it may not return is (radius of the planet is \[6.4\times {{10}^{6}}m,\,\,g=9.8\,m/se{{c}^{2}})\]           [AMU (Engg.) 1999]

    A)             \[9.8\times {{10}^{-3}}m/sec\]

    B)               \[12.8\times {{10}^{3}}m/sec\]

    C)             \[9.8\times {{10}^{3}}m/sec\]

    D)               \[11.2\times {{10}^{3}}m/sec\]

    Correct Answer: D

    Solution :

                    Escape velocity from surface of earth \[{{v}_{e}}=\sqrt{2gR}\] = \[\sqrt{2\times 9.8\times 6.4\times {{10}^{6}}}=11.2\times {{10}^{3}}\ m/s\]


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