A) 0.14 km/s
B) 0.5 km/s
C) 2.5 km/s
D) 5 km/s
Correct Answer: C
Solution :
On earth \[{{v}_{e}}=\sqrt{\frac{2GM}{R}}=11.2\,\,km/s\] On moon \[{{v}_{m}}=\sqrt{\frac{2GM\times 4}{81\times R}}=\frac{2}{9}\,\sqrt{\frac{2GM}{R}}\] \[=\frac{2}{9}\times 11.2=2.5\,\,km/s\]
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