JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Gravitation Potential

  • question_answer
    The escape velocity from the surface of earth is \[{{V}_{e}}\]. The escape velocity from the surface of a planet whose mass and radius are 3 times those of the earth will be [MP PMT/PET 1998; JIPMER 2001, 02; Pb. PMT 2004]

    A)             \[{{V}_{e}}\]

    B)             \[3{{V}_{e}}\]

    C)             \[9{{V}_{e}}\]          

    D)             \[27{{V}_{e}}\]

    Correct Answer: A

    Solution :

                    \[{{v}_{e}}=\sqrt{\frac{2GM}{R}}\]\ \[{{v}_{e}}\propto \sqrt{\frac{M}{R}}\] If mass and radius of the planet are three times than that of earth then escape velocity will be same.


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