JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Gravitation Potential

  • question_answer
    Escape velocity on a planet is \[{{v}_{e}}\]. If radius of the planet remains same and mass becomes 4 times, the escape velocity becomes                                  [MP PMT 1996; DPMT 1999]

    A)             \[4\,{{v}_{e}}\]         

    B)             \[2\,{{v}_{e}}\]

    C)             \[{{v}_{e}}\] 

    D)             \[\frac{1}{2}{{v}_{e}}\]

    Correct Answer: B

    Solution :

        \[{{v}_{e}}=\sqrt{\frac{2GM}{R}}\]Þ \[{{v}_{e}}\propto \sqrt{M}\] if \[R=\text{constant}\] If the mass of the planet becomes four times then escape velocity will become 2 times.


You need to login to perform this action.
You will be redirected in 3 sec spinner