JEE Main & Advanced Physics Gravitation / गुरुत्वाकर्षण Question Bank Gravitation Potential

  • question_answer
    The escape velocity of an object from the earth depends upon the mass of the earth (M), its mean density \[(\rho )\], its radius (R) and the gravitational constant (G). Thus the formula for escape velocity is                           [MP PMT 1995]

    A)             \[v=R\sqrt{\frac{8\pi }{3}G\rho }\]

    B)               \[v=M\sqrt{\frac{8\pi }{3}GR}\]

    C)             \[v=\sqrt{2GMR}\]

    D)               \[v=\sqrt{\frac{2GM}{{{R}^{2}}}}\]

    Correct Answer: A

    Solution :

       


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